人脸部分字典的在线学习#
本例使用一个大型人脸数据集来学习一组构成人脸的 20 x 20 图像块。
从编程的角度来看,这很有趣,因为它展示了如何使用 scikit-learn 的在线 API 分块处理非常大的数据集。我们的处理方式是一次加载一张图像,并从该图像中随机提取 50 个图像块。一旦我们积累了 500 个这样的图像块(使用 10 张图像),我们就运行在线 KMeans 对象 MiniBatchKMeans 的 partial_fit
方法。
MiniBatchKMeans 上的详细设置使我们能够看到在连续调用 partial-fit 期间,某些聚类被重新分配。这是因为它们所代表的图像块数量变得太少,最好选择一个随机的新聚类。
加载数据#
from sklearn import datasets
faces = datasets.fetch_olivetti_faces()
downloading Olivetti faces from https://ndownloader.figshare.com/files/5976027 to /home/circleci/scikit_learn_data
学习图像字典#
import time
import numpy as np
from sklearn.cluster import MiniBatchKMeans
from sklearn.feature_extraction.image import extract_patches_2d
print("Learning the dictionary... ")
rng = np.random.RandomState(0)
kmeans = MiniBatchKMeans(n_clusters=81, random_state=rng, verbose=True, n_init=3)
patch_size = (20, 20)
buffer = []
t0 = time.time()
# The online learning part: cycle over the whole dataset 6 times
index = 0
for _ in range(6):
for img in faces.images:
data = extract_patches_2d(img, patch_size, max_patches=50, random_state=rng)
data = np.reshape(data, (len(data), -1))
buffer.append(data)
index += 1
if index % 10 == 0:
data = np.concatenate(buffer, axis=0)
data -= np.mean(data, axis=0)
data /= np.std(data, axis=0)
kmeans.partial_fit(data)
buffer = []
if index % 100 == 0:
print("Partial fit of %4i out of %i" % (index, 6 * len(faces.images)))
dt = time.time() - t0
print("done in %.2fs." % dt)
Learning the dictionary...
[MiniBatchKMeans] Reassigning 8 cluster centers.
[MiniBatchKMeans] Reassigning 5 cluster centers.
Partial fit of 100 out of 2400
[MiniBatchKMeans] Reassigning 3 cluster centers.
Partial fit of 200 out of 2400
[MiniBatchKMeans] Reassigning 1 cluster centers.
Partial fit of 300 out of 2400
[MiniBatchKMeans] Reassigning 3 cluster centers.
Partial fit of 400 out of 2400
Partial fit of 500 out of 2400
Partial fit of 600 out of 2400
Partial fit of 700 out of 2400
Partial fit of 800 out of 2400
Partial fit of 900 out of 2400
Partial fit of 1000 out of 2400
Partial fit of 1100 out of 2400
Partial fit of 1200 out of 2400
Partial fit of 1300 out of 2400
Partial fit of 1400 out of 2400
Partial fit of 1500 out of 2400
Partial fit of 1600 out of 2400
Partial fit of 1700 out of 2400
Partial fit of 1800 out of 2400
Partial fit of 1900 out of 2400
Partial fit of 2000 out of 2400
Partial fit of 2100 out of 2400
Partial fit of 2200 out of 2400
Partial fit of 2300 out of 2400
Partial fit of 2400 out of 2400
done in 1.28s.
绘制结果#
import matplotlib.pyplot as plt
plt.figure(figsize=(4.2, 4))
for i, patch in enumerate(kmeans.cluster_centers_):
plt.subplot(9, 9, i + 1)
plt.imshow(patch.reshape(patch_size), cmap=plt.cm.gray, interpolation="nearest")
plt.xticks(())
plt.yticks(())
plt.suptitle(
"Patches of faces\nTrain time %.1fs on %d patches" % (dt, 8 * len(faces.images)),
fontsize=16,
)
plt.subplots_adjust(0.08, 0.02, 0.92, 0.85, 0.08, 0.23)
plt.show()
脚本总运行时间:(0 分钟 3.825 秒)
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